Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 11 - Three-Dimensional Space; Vectors - 11.1 Rectangular Coordinates In 3-Space; Spheres; Cylindrical Surfaces - Exercises Set 11.1 - Page 771: 10

Answer

See explanation.

Work Step by Step

The distance between two points: $\left(x_{1}, y_{1}, z_{1}\right)$ and $\left(x_{2}, y_{2}, z_{2}\right)$ is \[ Distance=\sqrt{\left(y_{1}-y_{2}\right)^{2}+\left(z_{1}-z_{2}\right)^{2}+\left(x_{1}-x_{2}\right)^{2}} \] Distance between (1,7,3) and (4,5,2) is \[ \sqrt{(-7+5)^{2}+(-3+2)^{2}+(-1+4)^{2}}=\sqrt{1+4+9}=\sqrt{14} \] Distance between (2,4,5) and (4,5,2) is \[ \sqrt{(-4+5)^{2}+(-5+2)^{2}+(-2+4)^{2}}=\sqrt{9+1+4}=\sqrt{14} \] Distance between (2,4,5) and (1,7,3) is \[ \sqrt{(-4+7)^{2}+(-5+3)^{2}+(-2+1)^{2}}=\sqrt{4+9+1}=\sqrt{14} \] Since the lengths of the three sides are equal, that is an equilateral triangle.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.