Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 2 - Section 2.6 - Limits at Infinity; Horizontal Asymptotes - 2.6 Exercises - Page 140: 71

Answer

N = 15

Work Step by Step

We can graph the function $f(x) = \frac{3x^2+1}{2x^2+x+1}$ On the graph , we can see that $~~1.45 \lt f(x) \lt 1.5~~$ when $~~x \gt 15$ Therefore: If $x \gt 15,~~~$ then $~~~\vert \frac{3x^2+1}{2x^2+x+1} - 1.5 \vert \lt 0.05$ We can check the value $N=15$ in the function: $f(15) = \frac{3(15)^2+1}{2(15)^2+(15)+1} = 1.4506$
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