Answer
$\lim\limits_{x \to 0^+}ln~x = -\infty$
Work Step by Step
Let $M \lt 0$ be given.
Let $\delta = e^M$
If $x - 0 \lt \delta$, then $ln(x) \lt ln(\delta) = ln(e^M) = M$
Therefore, $\lim\limits_{x \to 0^+}ln~x = -\infty$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 2 - Section 2.4 - The Precise Definition of a Limit - 2.4 Exercises - Page 114: 43
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