Answer
One common solution $\Rightarrow$ $(-4,-5\frac{1}{3})$
Work Step by Step
We use the addition method:
We add the 2 equations:
$4x-3y=0$
$2x-3y=8$
Multiply both sides of the second equation by $-2$ to cancel $x$.
$+4x-3y=0$
$\underline{-4x+6y=-16}$
$3y=-16$
Solve for $y$:
$y=\frac{-16}{3}$
Substitute into any of the two equations and solve for $x$:
$4x-3y=0$
$4x-3(-16/3)=0$
$4x+16=0$
$4x=-16$
$x=-4$
