Answer
One common solution $\Rightarrow$ $(1,0)$
Work Step by Step
We use the addition method below:
We add the 2 equations:
$2x+3y=2$
$3x-2y=3$
Multiply the first equation by $3$ and the second equation by $-2$ to cancel $x$:
$+6x+9y=6$
$\underline{-6x+4y=-6}$
$13y=0$
Solve for $y$:
$y=\frac{0}{13}=0$
Substitute into any of the two equations and solve for $x$:
$2x+3(0)=2$
$2x=2$
$x=\frac{2}{2}$
$x=1$
