Answer
$C_{1}=3.85*10^{-12}F$.
Work Step by Step
Given
$\frac{1}{C}=\frac{1}{C_{1}}+\frac{1}{C_{2}}+\frac{1}{C_{3}}$
$C=1.75*10^{-12}F, C_{1}=?, C_{2}=7.25*10^{-12}F, C_{3}=5.75*10^{-12}F$
$\frac{1}{1.75*10^{-12}}=\frac{1}{C_{1}}+\frac{1}{7.25*10^{-12}}+\frac{1}{5.75*10^{-12}}$
$\frac{1}{C_{1}}=\frac{10^{12}}{1.75}-(\frac{10^{12}}{7.25}+\frac{10^{12}}{5.75})$
$\frac{1}{C_{1}}=10^{12}(\frac{1}{1.75}-(\frac{1}{7.25}+\frac{1}{5.75}))$
Therefore, $C_{1}=3.85*10^{-12}$
How to use the calculator:
$1.75*x^{-1}-7.25*x^{-1}-5.75*x^{-1}=x^{-1}=$
