Answer
$C=1.74*10^{-8}F$.
Work Step by Step
Given
$\frac{1}{C}=\frac{1}{C_{1}}+\frac{1}{C_{2}}+\frac{1}{C_{3}}$
$C=?, C_{1}=6.56*10^{-7}, C_{2}=5.05*10^{-6}F, C_{3}=1.79*10^{-8}F$
$\frac{1}{C}=\frac{1}{6.56*10^{-7}}+\frac{1}{5.05*10^{-6}}+\frac{1}{1.79*10^{-8}}$
$\frac{1}{C}=\frac{10^{7}}{6.56}+\frac{10^{6}}{5.05}+\frac{10^{8}}{1.79}$
$\frac{1}{C}=10^{6}(\frac{1}{0.656}+\frac{1}{5.05}+\frac{1}{0.0179})$
Therefore,
$C=0.0173646*10^{-6}~F\approx 1.74*10^{-8}~F$
How to use the calculator:
$0.656*x^{-1}+5.05*x^{-1}+0.0179*x^{-1}=x^{-1}=$
