Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 6 - Section 6.8 - Substituting Data into Formulas - Exercises - Page 258: 5

Answer

$20\bar{0}0$

Work Step by Step

To solve the given equation for $m$, we multiply both sides by $2$ and then divide both sides by $v^2$ as follows $$ E=\frac{mv^2}{2}\Longrightarrow 2 E= mv^2 \Longrightarrow m=\frac{2E}{v^2} .$$ Now, by substitution, we have $$ m=\frac{2E}{v^2}=\frac{2\times 484,000}{22^2}=20\bar{0}0 .$$
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