Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 6 - Section 6.8 - Substituting Data into Formulas - Exercises - Page 258: 14

Answer

$$ \frac{ Q+WCT_2}{WC}\ , \ 94 .$$

Work Step by Step

To solve the given equation for $T_1$, we move out the term $WCT_2$ and then we divide both sides by $WC$ as follows $$ Q= WC(T_1-T_2) \Longrightarrow Q=WCT_1-WCT_2 \Longrightarrow WCT_1=Q+WCT_2\Longrightarrow T_1=\frac{ Q+WCT_2}{WC} .$$ Now, by substitution, we have $$ T_1=\frac{ Q+WCT_2}{WC}=\frac{ 18.9+3\times0.18\times59}{3\times0.18}=94 .$$
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