Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 6 - Section 6.8 - Substituting Data into Formulas - Exercises - Page 258: 16

Answer

$$ \frac{2A-bh}{h}, \ \ 21\bar{0} .$$

Work Step by Step

To solve the given equation for $a$, we multiply both sides by $2$ and then we follow the following steps: $$ A=\frac{(a+b)}{2}h \Longrightarrow 2 A=(a+b) h \Longrightarrow 2 A=ah+bh\\ \Longrightarrow 2A-bh=ah\\ \Longrightarrow a=\frac{2A-bh}{h}.$$ Now, we have $$ a=\frac{2A-bh}{h}=\frac{2\times5502-183\times28}{28}=21\bar{0} .$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.