Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 6 - Section 6.8 - Substituting Data into Formulas - Exercises - Page 258: 17

Answer

$$ \frac{2V-lwD}{lw}, \ \ 3.00 .$$

Work Step by Step

To solve the given equation for $d$, we multiply both sides by $2$ and then we follow the following steps: $$ V=\frac{1}{2}lw(D+d) \Longrightarrow 2 V=lw(D+d) \Longrightarrow 2 V=lwD+lwd \\ \Longrightarrow 2V-lwD=lwd \Longrightarrow d=\frac{2V-lwD}{lw}.$$ Now, we have $$ d=\frac{2V-lwD}{lw}=\frac{2\times226.8-9\times 6.3\times 5}{9\times 6.3}=3.00 .$$
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