Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 6 - Section 6.6 - Applications Involving Equations - Exercises - Page 252: 6

Answer

The answer is: $\$550$ to John, $\$1100$ to Maria and $\$3300$ to Betsy.

Work Step by Step

We assign the variables: x = John's money y = Maria's money z = Betsy's money Step 1: Find the equations that represent the problem. We know $x+y+z=4950$, because the addition of the money given to each one has to equal the total amount of money. $x+y+z=4950$ -> Eq. 1 We can get the second equation from the wording in the problem. From "Maria receives twice as much as John", we get: $y=2x$ -> Eq. 2 We can get the third equation from the wording in the problem. From "Betsy receives three times as much as Maria", we get: $z=3y$ -> Eq. 3 Step 2: Solve the system of equations. Using the substitution method, -> Substitute eq. 2 into eq. 3 $z=3(2x)$ -> to find z in terms of x $z=6x$ -> Eq. 4 -> Substitute eq. 2 and eq. 4 into eq. 1 $x+2x+6x=4950$ $9x=4950$ $x=\frac{4950}{9}$ $x=550$ -> Substitute the value for x in eq. 2 $y=2(550)$ $y=1100$ -> Substitute the value for y in eq. 3 $z=3(1100)$ $z=3300$ Step 3: The answer is: $\$550$ to John, $\$1100$ to Maria and $\$3300$ to Betsy.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.