Answer
The maximum number of deer that it will support is 399 white-tailed deer.
Work Step by Step
We assign the variable:
x = maximum number of deer
Step 1:
Find the equation that represents the problem.
We can get the equation from the wording in the problem.
From "A white-tailed deer requires 0.25 AEU of grazing capacity and an elk requires 0.67 AEU" and "a state park will provide grazing to support about 150 AEUs", we get:
deer AEU + elk AEU = Total AEU
$0.25x+0.67(75)=150$
Step 2:
Solve for x.
$0.25x+50.25=150$
$0.25x=150-50.25$
$0.25x=99.75$
$x=\frac{99.75}{0.25}$
$x=399
Step 3:
The maximum number of deer that it will support is 399 white-tailed deer.
