Answer
$A=37.15^{\circ}$.
$B=52.85^{\circ}$.
$c=2070\;km$.
Work Step by Step
The given values are
$a=1250\;km$
$b=1650\;km$.
By using trigonometric ratios.
$\frac{a}{b}=\tan{A}$
Isolate $A$.
$A=\tan^{-1}\left(\frac{a}{b} \right )$
Plug all values.
$A=\tan^{-1}\left(\frac{1250\;km}{1650\;km} \right )$
By using degree calculator simplify.
$A=37.15^{\circ}$ (rounded value).
In a right angle triangle sum of other two angles is $90^{\circ}$.
$A+B=90^{\circ}$
Isolate $B$.
$B=90^{\circ}-A$
Plug value of $A$.
$B=90^{\circ}-37.15^{\circ}$
Simplify.
$B=52.85^{\circ}$.
By using Pythagorean theorem.
$c=\sqrt{a^2+b^2}$
Plug all values.
$c=\sqrt{(1250\;km)^2+(1650\;km)^2}$
Simplify.
$c=\sqrt{1562500\;km^2+2722500\;km^2}$
$c=\sqrt{(4285000\;km^2)}$
$c=2070\;km$ (rounded value).
