Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.8 - Cylinders - Exercise - Page 427: 15

Answer

(a.)$2048 \; mm^2$. (b.)$2471\;mm^2 $.

Work Step by Step

Given values are:- Radius $r=8.21\; mm$. Height $h=39.7\; mm$. (a.) Formula for the lateral surface area is $A=2\pi rh$ Substitute all values. $A=2\pi (8.21\;mm)(39.7\;mm)$ Simplify. $A=2048 \; mm^2$ (rounded value.) (b.) The area of the bases is $=2\pi r^2$ Substitute all values. $=2\pi (8.21)^2$ Simplify. $=423 \; mm^2$ (rounded value.) Total surface are $=$ Lateral surface area $+$ Area of the bases. Substitute all values. $=2048\;mm^2+423\;mm^2 $ Simplify. $=2471\;mm^2 $.
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