Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.8 - Cylinders - Exercise - Page 427: 11

Answer

$1.79\; in$.

Work Step by Step

The length of the cylinder is $h=10.0\; in$. The volume of the cylinder is $V=25.3\; in^3$. The formula for volume is: $V=\pi r^2 h$ Isolate $r$. $r=\sqrt{\frac{V}{\pi h}}$ Plug all values. $r=\sqrt{\frac{25.3\; in^3}{\pi (10\; in)}}$ Simplify. $r=0.89739846893\; in$ Diameter $d=2r$. $d=2(0.89739846893\; in)$ $d=1.79479693787\; in$ Rounded to two decimal places. $d=1.79\; in$.
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