Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.8 - Cylinders - Exercise - Page 427: 10

Answer

$113.1\; in^3$.

Work Step by Step

Diameter of the cylindrical rod is $d = 3.0\; in$. Radius $r=\frac{d}{2}$. $r=\frac{3.0\; in}{2}$ Length $h=16\;in$. The formula for volume is: $V=\pi r^2 h$ Plug all values. $V=\pi (\frac{3.0\; in}{2})^2 (16\; in)$ Simplify (rounded to the nearest one decimal). $V=113.1\; in^3$.
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