Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.8 - Cylinders - Exercise - Page 428: 16

Answer

(a.)$6367\;cm^2$ (b.)$8781\;cm^2$.

Work Step by Step

Given values are:- Diameter $d=39.2\; cm$ Radius $r=\frac{d}{2}$ $r=\frac{39.2}{2}\;cm$ $r=19.6\;cm$ Height $h=51.7\; cm$. (a.) Formula for the lateral surface area is $A=2\pi rh$. Substitute all values. $A=2\pi (19.6\;cm)(51.7\;cm)$ Simplify. $A=6367 \; cm^2$ (Rounded value.) (b.) The area of the bases $=2\pi r^2$ Substitute all values. $=2\pi (19.6\;cm)^2$ Simplify. $=2414 \; cm^2$ (rounded value.) Total surface are $=$ Lateral surface area $+$ Area of the bases. Substitute all values. $=6367\;cm^2+2414\;cm^2 $ Simplify. $=8781\;cm^2 $.
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