Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.3 - Triangles - Exercise - Page 400: 36

Answer

$A=274.1m^{2}\approx274m^{2}$ $P=82.3m$

Work Step by Step

To find the area of the triangle, we use the formula: $A=\frac{bh}{2}$ So, $A=\frac{bh}{2}=\frac{(19.1m)(28.7m)}{2}=274.1m^{2}\approx274m^{2}$ To find the perimeter, we add the lengths of all the sides. However, we are missing the hypotenuse of the triangle, so we use the Pythagorean Theorem to find it. $c^{2}=a^{2}+b^{2}$ $c=\sqrt {a^{2}+b^{2}}=\sqrt {(19.1m)^{2}+(28.7m)^{2}}=34.47m\approx34.5m$ $P=19.1m+28.7m+34.5m=82.3m$
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