Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.3 - Triangles - Exercise - Page 400: 34

Answer

$A=48.3~cm^{2}$ $P=35.7~cm$

Work Step by Step

To find the area of a triangle, we use the formula: $A=\frac{bh}{2}$. Thus, we have: $A=\frac{bh}{2}=\frac{(15.6cm)(6.19cm)}{2}=48.28~cm^{2}\approx 48.3~cm^2$ To find the perimeter, we add the lengths of all the sides: $P=9.29cm+15.6cm+10.8cm=35.69~cm\approx 35.7~cm$
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