Answer
$V_{resistor} = 397~V$
Work Step by Step
The voltage across the resistor can be calculated as one of the sides of the right triangle by using the Pythagorean Theorem:
$V_{resistor}^2+(362V)^2=(537V)^{2}$
$V_{resistor}=\sqrt {(537V)^{2} - (362V)^{2}} = 396.64~V\approx 397~V$
