Answer
$I_{coil}=21.17A\approx21A$
Work Step by Step
The current passing through the coil can be calculated as one of the sides of the right triangle by using the Pythagorean Theorem.
$I_{total}^{2}=I_{resistor}^{2}+I_{coil}^{2}$
$I_{coil}=\sqrt {I_{total}^{2}-I_{resistor}^{2}}$
$I_{coil}=\sqrt {(32A)^{2}-(24A)^{2}}=21.17A\approx21~A$
