Answer
$$43.34\ cm\, \ 102\ cm^2.$$
Work Step by Step
The perimeter of the given quadrilateral is
$$sum\ of \ sides=10.21+9.59+15.63+7.91=43.34\ cm$$
The area is given by
$$\frac{1}{2} (sum\ of\ parallel\ bases)\times hight=\frac{1}{2}(10.21+15.63)\times7.91=102.1972\ cm^2\approx 102~cm^2.$$
