Answer
$$36\ cm\ , \ 60\ cm^2$$
Work Step by Step
The perimeter of the given quadrilateral is
$$sum\ of \ sides=2(6+12)=2(18)=36\ cm$$
The area is given by
$$base \times hight=12\times5=60\ cm^2$$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 12 - Review - Page 443: 7
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