Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Review - Page 443: 13

Answer

$159.5 \ m, \ 796\ m^2$

Work Step by Step

Since the perimeter of a triangle is the sum of the lengths of the sides, then we have $$perimeter=46+73.9+39.6=159.5 \ m .$$ Also, the area is given by $$ Area= \frac{1}{2} base \times hight=\frac{1}{2}\times39.6\times 40.2=795.96\ m^2\approx 796~m^2 .$$
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