Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Review - Page 443: 12

Answer

$58.7 \ m, \ 159\ m^2.$

Work Step by Step

Since the perimeter of a triangle is the sum of the lengths of the sides, then we have $$perimeter=16.5+21.9+20.3=58.7 \ m .$$ Also, the area is given by $$ Area= \frac{1}{2} base \times hight=\frac{1}{2}\times20.3\times 15.7=159.355\ m^2\approx 159 ~m^2 .$$
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