Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Cumulative Review - Page 447: 28

Answer

$$191~cm^2, \ 49.0~cm$$

Work Step by Step

The area and circumference of the circle are given by: $$Area=r^2 \pi= (15.6/2)^2\pi=191.13\ cm^2\approx 191~cm^2$$ $$Circumference= 2r \pi=15.6\pi \ cm=49.008\ cm \approx 49.0~cm.$$
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