Answer
$0.4, \ or, \ -3$
Work Step by Step
For the equation $5x^2 +13x-6 = 0$, we use the quadratic formula as follows
$$
x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a},
\\
a=5, \quad b=13, \quad c=-6
.$$
That is, $$ x=\frac{-13 \pm \sqrt{13^2+4(5)(6)}}{10 }=0.4, \ or, \ -3
.$$
