Answer
$\frac{3}{2}=1.5, \ or, \ -1$
Work Step by Step
For the equation $2x^2 -x-3 = 0$, we use the quadratic formula as follows
$$
x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a},
\\
a=2, \quad b=-1, \quad c=-3
.$$
That is, $$ x=\frac{1 \pm \sqrt{1+4(2)(3)}}{4 }=\frac{3}{2}=1.5, \ or, \ -1
.$$
