Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Cumulative Review - Page 447: 18

Answer

$(x-7)(x+4)$

Work Step by Step

We need to factor: $x^2 - 3x -28$ The first term in each binomial must be $x$, since $x^2$ has no coefficient. The operation in each binomial must be subtraction and addition since the second term in the trinomial is negative and the third term is negative. Since $-7+4=-3$ and $(-7)(4)=-28$, the other two terms are $-7$ and $4$. Thus, we have: $x^2 - 3x -28 =(x-7)(x+4)$
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