Answer
16$\frac{1}{2}$ ft
Work Step by Step
Lets consider the house built on 65 $\frac{3}{4}$ ft wide lot
The house is 5$\frac{5}{12}$ ft wide from one side of the lot and is 43 $\frac{5}{6}$ ft wide
Distance from the other side of the lot = 65 $\frac{3}{4}$ ft - 5$\frac{5}{12}$ ft - 43 $\frac{5}{6}$ ft
=$\frac{263}{4}$ - $\frac{65}{12}$ - $\frac{263}{6}$
=$\frac{263}{4}\times$ $\frac{3}{3}$ -$\frac{65}{12}$ -$\frac{263}{6}\times$ $\frac{2}{2}$
=$\frac{789}{12}$ - $\frac{65}{12}$ - $\frac{526}{12}$
=$\frac{198}{12}$
=$\frac{33}{2}$
=16$\frac{1}{2}$ ft
