Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.7 - Addition and Subtraction of Fractions - Exercise - Page 42: 75

Answer

14 $\frac{3}{8}$ in

Work Step by Step

Floor joist spaces are 16 in and 1$\frac{5}{8}$in Distance between them = 16in – 1$\frac{5}{8}$in =$ 16 \times$ $\frac{8}{8}$ - $\frac{13}{8}$ =$\frac{128}{8}$ - $\frac{13}{8}$ =$\frac{115}{8}$ =14 $\frac{3}{8}$ in
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