Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.7 - Addition and Subtraction of Fractions - Exercise - Page 42: 77

Answer

$\frac{5}{64}$ in

Work Step by Step

Lets consider the diameter of the shaft is $\frac{7}{8}$ in We have to find the length that must be reduced so that the diameter of the shaft is $\frac{51}{64}$ in. Therefore length = $\frac{7}{8}$ in - $\frac{51}{64}$ in. = $\frac{7}{8}\times$ $\frac{8}{8}$ - $\frac{51}{64}$ = $\frac{56}{64}$ - $\frac{51}{64}$ =$\frac{5}{64}$ in
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.