Answer
(a) $\frac{21}{2}$in
(b) $\frac{3}{4}$in
Work Step by Step
For (a), you just need to simply add all 3 sides of the tool.
So, 6$\frac{7}{8}$in + 1$\frac{3}{8}$in + 2$\frac{1}{4}$in.
To add mixed numbers, we can separate the mixed number like so: 6 +$\frac{7}{8}$ + 1 + $\frac{3}{8}$ + 2 + $\frac{1}{4}$
Using the maximum common divisor, which in this case is 8, we just add all three fractions and add the 3 whole numbers.
=> 9 + $ \frac{7+3+2(1)}{8}$ = 9 + $\frac{12}{8}$
Adding the whole number and the new fraction, we get
= $\frac{21}{2}$in, and this is the length of the tool.
For (b), to find the diameter A, we just need to subtract the two $\frac{7}{16}$in-sections from the total diameter of the tool, which is 1$\frac{5}{8}$in.
So, A = 1$\frac{5}{8}$in - $\frac{7}{16}$in - $\frac{7}{16}$in. Using the same procedure as in (a), we get
=> A = $\frac{3}{4}$in
