Chapter 5 - Section 5.3 - Special Products - Exercise Set - Page 367: 6

$3x^2+16x-35$

Using $(a+b)(c+d)=ab+ad+bc+bd$ or the FOIL Method, the product of the given expression, $ (3x-5)(x+7) ,$ is \begin{array}{l}\require{cancel} 3x(x)+3x(7)-5(x)-5(7) \\\\= 3x^2+21x-5x-35 \\\\= 3x^2+16x-35 .\end{array}