Answer
$21x^4-41x^2+10$
Work Step by Step
Using $(a+b)(c+d)=ab+ad+bc+bd$ or the FOIL Method, the product of the given expression, $
(7x^2-2)(3x^2-5)
,$ is
\begin{array}{l}\require{cancel}
7x^2(3x^2)+7x^2(-5)-2(3x^2)-2(-5)
\\\\=
21x^4-35x^2-6x^2+10
\\\\=
21x^4-41x^2+10
.\end{array}
