Answer
$x = \frac{1}{3}$
$b^2 - 4ac = 0$
Work Step by Step
$9x^2 - 6x + 1 = 0$ is in the form $ax^2+bx+c$.
To solve by factoring:
Find two First terms whose product is $ax^2$:
$(3x +$ __ $)$$(3x+$ __ $)$
Find two Last terms whose product is $c$:
$(3x + 1 )(3x+ 1 )$ combination 1
$(3x - 1 )(3x- 1 )$ combination 2
Check for combination 1:
$(3x + 1 )(3x+ 1 )$
$(3x + 1 )(3x+ 1 ) = (3x)(3x) +3x + 3x +1$
$(3x + 1 )(3x+ 1 ) = 9x^2 + 6x +1$
Check for combination 2:
$(3x - 1 )(3x- 1 ) = (3x)(3x) - 3x-3x +1$
$(3x - 1 )(3x- 1 ) = 9x^2 - 6x +1$
