Answer
TRUE.
The x-intercepts are imaginary numbers $2 ± \sqrt 3i$. Thus, the graph of the equation $y = (x - 2)^2 + 3$ will not have x-intercepts.
Work Step by Step
TRUE.
$y = (x - 2)^2 + 3$
To get the x-intercept, set the $y$ value to zero.
$0 = (x - 2)^2 + 3$
$-3 = (x - 2)^2$
$x = 2 ± \sqrt 3i$
