Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 578: 99

Answer

$\frac{1}{3}-\frac{5}{3}i$.

Work Step by Step

The given expression is $=\frac{5+i}{3i}$ Multiply the numerator and the denominator by $3i$. $=\frac{5+i}{3i}\cdot \frac{3i}{3i}$ Use the distributive property in the numerator. $=\frac{15i+3i^2}{9i^2}$ Use $i^2=-1$. $=\frac{15i-3}{-9}$ Rewrite as $a+ib$. $=\frac{-3}{-9}+\frac{15}{-9}i$ Simplify. $=\frac{1}{3}-\frac{5}{3}i$.
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