Answer
$1$
Work Step by Step
Solve $i^{16}$
Since, $i^2=-1$ and $i^2 \cdot i^2=(-1)(-1)=1$
Thus,
$i^{16}=(i^2)^4 \cdot (i^2)^4=(-1)^4(-1)^4=(1)^4=1$
Hence, $i^{16}=1$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Review Exercises - Page 578: 100
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
