Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 578: 98

Answer

$\frac{1}{5}+\frac{11}{10}i$.

Work Step by Step

The given expression is $=\frac{3+4i}{4-2i}$ The conjugate of the denominator is $4+2i$. Multiply the numerator and the denominator by $4+2i$. $=\frac{3+4i}{4-2i}\cdot \frac{4+2i}{4+2i}$ Use the special formula $(A+B)^2=A^2+2AB+B^2$ $=\frac{12+6i+16i+8i^2}{(4)^2-(2i)^2}$ Use $i^2=-1$. $=\frac{12+22i-8}{16+4}$ Simplify. $=\frac{4+22i}{20}$ Rewrite as $a+ib$. $=\frac{4}{20}+\frac{22}{20}i$ Simplify. $=\frac{1}{5}+\frac{11}{10}i$.
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