Answer
$29+11i$
Work Step by Step
Solve.$(7-5i)(2+3i)$
we have, $=7(2+3i)-5i(2+3i)$
Need to drop the parentheses and multiply the terms.
$=14+21i-10i-15i^2$
Since, $i^2=-1$
Thus, $=14+11i-15(-1)$
or, $=29+11i$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Review Exercises - Page 578: 93
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