Answer
$\frac{x^2}{15(x+2)}$.
Work Step by Step
The given expression is
$=\frac{8x^2}{3x^2-12}\div \frac{40}{x-2}$
Invert the divisor and multiply.
$=\frac{8x^2}{3x^2-12}\times \frac{x-2}{40}$
Factor $3x^2-12$.
Factor out $3$.
$\Rightarrow 3(x^2-4)$
$\Rightarrow 3(x^2-2^2)$
Use the special formula $A^2-B^2=(A+B)(A-B)$ in the denominator.
$\Rightarrow 3(x+2)(x-2)$
$=\frac{8x^2}{3(x+2)(x-2)}\times \frac{x-2}{40}$
Cancel common terms.
$=\frac{x^2}{15(x+2)}$.
