Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Cumulative Review Exercises - Page 579: 20

Answer

$2650$ students.

Work Step by Step

Let the number of students enrolled last year $=100\%$. This year $12\%$ fewer students enrolled $=100-12=88\%$ The number of students enrolled in the college this year is $=2332$. Equate both values. $\Rightarrow 88\%=2332$. Divide both sides by $88$. $\Rightarrow \frac{88}{88}\%=\frac{2332}{88}$. Simplify. $\Rightarrow 1\%=26.5$. Multiply both sides by $100$. $\Rightarrow 100\times 1\%=100\times 26.5$. Simplify. $\Rightarrow 100\%=2650$. Hence, the number of students were enrolled last year $=2650$.
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