Answer
$(4x^2+1)(2x+1)(2x-1)$
Work Step by Step
The product of a binomial sum and a binomial difference is: $(A+B)(A-B)=A^2-B^2$.
Hence here: $16x^4-1=(4x^2)^2-1^2=(4x^2+1)(4x^2-1)=(4x^2+1)((2x)^2-1^2)=(4x^2+1)(2x+1)(2x-1)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Cumulative Review Exercises - Page 579: 17
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