Answer
$(x+y^2)(3x+2y^2)$
Work Step by Step
The product of a binomial sum and a binomial difference is: $(A+B)(A-B)=A^2-B^2$.
The square of a binomial sum is: $(A+B)^2=A^2+2AB+B^2$.
The square of a binomial difference is: $(A-B)^2=A^2-2AB+B^2$.
Hence here: $3x^2+5xy^2+2y^4=\\=3x^2+3xy^2+2xy^2+2y^4\\=3x(x+y^2)+2y^2(x+y^2)\\=(x+y^2)(3x+2y^2)$
