Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.6 - A General Factoring Strategy - Exercise Set - Page 379: 53

Answer

$y(14y^2+7y-10)$.

Work Step by Step

The given expression is $=14y^3+7y^2-10y$ Factor the expression as shown below. $=14y^2\cdot y+7y\cdot y-10\cdot y$ Factor out the common term. $=y(14y^2+7y-10)$.
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