Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.6 - A General Factoring Strategy - Exercise Set - Page 379: 40

Answer

$(3x^2+8)(x+3)$

Work Step by Step

$3x^3+8x+9x^2+24=\\=x(3x^2+8)+3(3x^2+8)\\=(3x^2+8)(x+3)$
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