Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 363: 134

Answer

$a^2(a^{n}-3)(a^n+2)$.

Work Step by Step

The given expression is $=a^{2n+2}-a^{n+2}-6a^2$ $=a^{2n}a^2-a^{n}a^2-6a^2$ Factor out $a^2$. $=a^2(a^{2n}-a^{n}-6)$ Rewrite the term $-a^{n}$ as $-3a^{n}+2a^{n}$. $=a^2(a^{2n}-3a^{n}+2a^{n}-6)$ Group terms. $=a^2[(a^{2n}-3a^{n})+(2a^{n}-6)]$ Factor from each group. $=a^2[a^n(a^{n}-3)+2(a^{n}-3)]$ Factor out $(a^n-3)$ $=a^2(a^{n}-3)(a^n+2)$.
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