Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 363: 133

Answer

$(4x^{n}-5)(x^n-1)$.

Work Step by Step

The given expression is $=4x^{2n}-9x^n+5$ Rewrite the term $-9x^n$ as $-5x^n-4x^n$. $=4x^{2n}-5x^n-4x^n+5$ Group terms. $=(4x^{2n}-5x^n)+(-4x^n+5)$ Factor each group. $=x^{n}(4x^n-5)-1(4x^n-5)$ Factor out $(x^n-1)$ $=(x^n-1)(4x^{n}-5)$. Rearrange. $=(4x^{n}-5)(x^n-1)$.
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